SBI PO REASONING QUESTIONS

SBI PO REASONING QUESTIONS

Instructions (1 – 5): Answer the questions on the basis of the information given below.

10 associates – A, B, C, D, E, P, Q, R, S, and T have birthdays in dissimilar months – January, March, April, June and September but not essentially in the same order. There birthdays in on 2 dissimilar dates -22 and 28. So in individual month there are 2 birthdays. There are two birthdays after the birthdays of B. There are two birthdays amid the birthdays of B and D. A and T have birthdays in March.

There is only one birthday between the birthday of A and P. P’s birthday is not in the same month as that of  D. There are an equal number of birthday between T and C as between B and Q. C’s birthday is not in April. Q’s birthday is in the month of having 30 days. No birthday is there in between the birthday of R and E. Also their birthdays are in different months. E’s birthday is exactly  in between the birthday of A and S.

 

1 .R’s birthday is on ?

A) 22 April

B) 28 March

C) 22 June

D) 28 April

E) None of these

Option C

2.Who has a birthday in April?

A) D

B) C

C) Q

D) P

E) B

Option A

3. How many birthdays are there in between the birthdays of E and Q?

A) Four

B) Two

C) Three

D) One

E) Six

Option C

4. Which of the following combination of Month- Person-Date is correct as per the given arrangement?

A) June – B – 22

B) April – R – 22

C) March – A – 22

D) January – C- 22

E) January – P – 28

Option C

5. Which of the following pair has a  birthday on 22nd of a month?

A) P, B

B) P, D

C) C, E

D) R, T

E) S, E

Option B

 

 Instructions (6 – 10): Answer the questions on the basis of the information given below.

There are 8 kids – A, B, C, D, E, F, G and H who live on dissimilar floors of a 8-floor building numbered 1 to 8 not essentially in the same order. They have Dissimilar chocolates – 11, 16, 19, 25, 34, 41, 46 and 50 again not necessarily in the same order. The one who be live on 6th no floor has 25 chocolates. One Children living between F and the one having 25 chocolates. G lives below F on a even number floor. G does not have 25 chocolates. The one kid  having 46 chocolates lives just above G. Two children Live between F and H.

H lives below F. The total of number of the chocolates with D and H is a multiple of  a 4. Two children living between A and the one having 41 chocolates. A lives above G. The one have 41 chocolates live above A. B has 34 chocolates. The one having 11 chocolates living just above  one having 16 chocolates. 1 child lives between C and E. The difference between the num. of chocolates with E and G is 6

6. How many children live above E?

A) 1

B) 2

C) 4

D) None

E) 5

Option B

7.Who has 41 chocolates?

A)C

B) E

C) F

D) H

E) B

Option A

8. Who lives on the third floor?

A)A

B) B

C) C

D) D

E) E

Option D

9.Which of the following is right with respect to the arrangement?

A) 2 children living between B and one having 25 chocolates

B) F lives on the floor above A.

C) A lives just below D

D) H has maximum chocolates

E) None of these is correct

Option D

10. What is the sum of chocolates with B and D?

A) 80

B) 83

C) 76

D) 96

E) 84

Option A

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PUZZLE 1-5

sbi po reasoning

PUZZLE 6-10

sbi po reasoning 1

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