# SBI PO MISSING DI QUESTIONS

**Instruction (1-5): The table given below shows the scorecard of India during a test match. Some values are missing. Find the answers based on information in a table and respective questions.**

**Player Runs Balls Faced 4’s 6’s**

**Virat Kohli 148 104 13 –**

**Suresh Raina 40 55 3 –**

**Ravi Ashwin 37 42 1 1**

**Chetswar Pujara – 21 2 0**

**Ravindra Jadeja 13 5 0 1**

**MS Dhoni 81 – 11 3**

**Total – – – 10**

**Further information is:**

**Further information is:**

**(i) Total runs scored by V Kohli from those scored by 1’s and 2’s are in the ratio of 1: 5**

**(ii) A number of white balls faced by C Pujara are 6.**

**(iii) A white ball is defined as the ball on which no run is scored.**

**(iv) During the entire match only 1’s, 2’s, 4’s and 6’s were taken by the batsmen.**

**(v) V Kohli hits the maximum number of 6’s among all the batsmen.**

**(vi) Beside C Pujara every player has hit at least a six.**

**(vii) Every player has taken at least a 1 and a 2.**

**1. What is the total number of white balls face by V Kohli?**

**A) 42**

**B) 53**

**C) 49**

**D) 45**

**E) 38**

**Answer**

**Option D**

**Solution:**

**Runs scored by 4’s = 13*4 = 52**

**Total 6’s = 10, Each player except Pujara hit at least a 6. And Kohli hit the maximum 6’s.**

**So 6’s by Kohli = 4. So runs scored by 6’s = 4*6 = 24**

**Total runs scored by 4’s and 6’s = 52+24 = 76**

**For these runs balls played are 13+4 = 17 …….(1)**

**So runs by 1’2 and 2’s = 148-76 = 72**

**1’s and 2’s runs ratio = 1 : 5**

**So 12 runs by 1’2 and 60(2*30) by 2’s**

**So balls for 1’s and 2’s = 12+30 = 42 ……..(2)**

**So total balls = 17+42 = 59**

**So number of white balls = 104 – 59 = 45**

**2. What is the minimum number of balls faced by MS Dhoni?**

**A) 24**

**B) 32**

**C) 29**

**D) 36**

**E) 20**

**Answer**

**Option A**

**Solution:**

**Runs scored by 4’s = 11*4 = 44 ….(1)**

**by 6’s = 3*6 = 18 ……(2)**

**Total runs by 4’s and 6’s = 44+18 = 62**

**remaining runs = 81-62 = 19**

**By taking 1’s and 2’s he has scored these 19 runs. To minimize the number of balls Dhoni has to score more runs taking 2’s. So he can score 18 runs by taking 2’s and 1 by taking a**

**1.**

**So balls for 1’s and 2’s = 9+1 = 10 …….(3)**

**So total balls (minimum) = 11+3+10 = 24**

**3.If the number of balls faced by C Pujara to take 1’s is greater than that for 2’s, then he can score a maximum of how many runs?**

**A) 24**

**B) 27**

**C) 32**

**D) 21**

**E) 34**

**Answer**

**Option B**

**Solution:**

**Runs by 4’s = 2*4 = 8 ….(1)**

**Number of white balls = 6**

**So remaining balls = 21 – (2+6) = 13**

**So, to maximize his score in 13 balls, he can take 7 ones and 6 two’s. ……(2)**

**So a maximum of 8 + 7*1 + 6*2 = 27 runs**

**4. Assume if only the given players score during the match for the team, then what is the minimum score of the team?**

**4. Assume if only the given players score during the match for the team, then what is the minimum score of the team?**

**A) 333**

**B) 309**

**C) 403**

**D) 358**

**E) 341**

**Answer**

**Option E**

**Solution:**

**In order to find the minimum score of a team, we have to find the minimum runs scored by**

**Pujara.**

**he takes 2 four’s so 2*4 = 8 runs**

**So now 21-2 = 19 balls left. Now given that he faced 6 white balls, So now balls left = 19-**

**6 = 13 balls. Now for minimum runs, he should score more 1’s than 2’s**

**Since at least one 1’s and one 2’s is necessary so minimum runs on 13 balls is 1*12 + 2*1**

**So total min runs by Pujara = 2*4 + 1*12 + 2*1 = 22**

**So minimum score of team = 148+40+37+22+13+81 = 341**

**5. What was the maximum possible new run rate of the team?**

**A) 9.32**

**B) 8.48**

**C) 7.56**

**D) 4.45**

**E) 12.23**

**Answer**

**Option B**

**Solution:**

**First, find the maximum runs scored and minimum balls faced.**

**Minimum number of balls faced by Dhoni = 24**

**Maximum runs scored by Pujara = 2*12 + 1*1 + 4*2 = 33**

**Maximum runs scored by team = 148+40+37+33+13+81 = 352**

**Minimum number of balls faced = 104+55+42+21+5+24 = 251 balls or 251/6 = 41.5 overs**

**So maximum run rate = 352/41.5 = 8.48**

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